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== operator: Ignore string context
There really is no case I can think of where taking the context into account is useful. Mostly it's just very inconvenient.
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3 changed files with 4 additions and 13 deletions
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@ -1355,17 +1355,8 @@ bool EvalState::eqValues(Value & v1, Value & v2)
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case tBool:
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return v1.boolean == v2.boolean;
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case tString: {
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/* Compare both the string and its context. */
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if (strcmp(v1.string.s, v2.string.s) != 0) return false;
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const char * * p = v1.string.context, * * q = v2.string.context;
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if (!p && !q) return true;
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if (!p || !q) return false;
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for ( ; *p && *q; ++p, ++q)
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if (strcmp(*p, *q) != 0) return false;
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if (*p || *q) return false;
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return true;
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}
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case tString:
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return strcmp(v1.string.s, v2.string.s) == 0;
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case tPath:
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return strcmp(v1.path, v2.path) == 0;
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@ -1297,7 +1297,7 @@ void EvalState::createBaseEnv()
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language feature gets added. It's not necessary to increase it
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when primops get added, because you can just use `builtins ?
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primOp' to check. */
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mkInt(v, 2);
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mkInt(v, 3);
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addConstant("__langVersion", v);
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// Miscellaneous
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@ -1,6 +1,6 @@
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let s = "foo ${builtins.substring 33 100 (baseNameOf ./eval-okay-context.nix)} bar";
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in
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if s == "foo eval-okay-context.nix bar"
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if s != "foo eval-okay-context.nix bar"
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then abort "context not discarded"
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else builtins.unsafeDiscardStringContext s
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